HM
3 3
3 1 2 3
3 AB BC CA
AB c 3
BC a 1
CA b 2
= 180
AB
= 8
BC
= 5
CA
-
3
90
90
90
3
-
3
90
90 90
-
3 90
AB AC
ABC ACB
CAB
BC
BD DC
3
3
3
ACB = 132
ABC = 123
AB = 12
3
-
1 + 2 + 3 = 180
a1 = b 2 = c 3
1 = 50
2 = 70
3 = 60
a
8
a1 = b 2
8 : 50
b : 70
b = 9.8
c
-
1 = 60
c
= 8
b
= 5
a = b + c
-
(2 b c 1 )
a =
55 + 88 - 25 8 60
25 + 64 - 40
a
= 49
a
a
a
= 7
(2 b c 1 )
90 =
=
a = b + c
=
3 8,5,7
= 8+5+7 = 20
= 1/2
= 3
= 4
= 1/2 34
= 6
= 1/2
= 1/2 34 90
90 = 1
= 6
=
( s (s-as-bs-c
s =
3 . 4 .5
= 3 +4+5 = 12
s
= 6
=
6 ( 6-5 6-4 6-3 )
6 6
=
36
= 6
Hassan Mohamed
+
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